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12n^2+8n+1=0
a = 12; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·12·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*12}=\frac{-12}{24} =-1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*12}=\frac{-4}{24} =-1/6 $
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